Notable

NOTABLES

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Notable because: you ALMOST finish with simple techniques. With only 18 remaining, a chain is required. And notable because it's one of the first chains you would try (assuming you start with top, left pairs). Nice intro to chains for novices.
PB Post 2014 03 29  Lvl 6 (Repeated lower down)

PB Post 2014 03 29 Lvl 6 w18  Same as above, except the gray boxes are filled in.

Note: Using "simple" methods, the underlined 5's (G4 and I5) can be removed as choices.

To proceed, a chain was found, beginning with the 5 in B4.  Then B9, G9, and G3.  This proves that G4 cannot equal 1, and so G4 must equal 9.   FINIS!

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Notable because:  Two solutions
PB Post 2013 11 28 Lvl 5   (Repeated lower down)

Below is the same puzzle (Nov 28) with blue boxes filled in. Most people can easily get this far. I then got stuck, with 41 blanks remaining.  Someone figured out somehow that G7 = 3.

PB Post 2013 11 28 Lvl 5 w 41            Same as above, except the blue boxes are filled in

Note: Using "simple" methods, the   underlined numbers (in ) can be removed as choices.
.I would not normally report this, but something unique (for me) happened later.
To proceed in puzzle above:
1. Fill in  3  for G7. I CANNOT explain WHY!!  (Lemme know if you can figure out why!!)
3. Fill in the other 30 grey boxes (shown below):

PB Post 2013 11 28 Lvl 5 w 10 (3rd SHOWING!) Same as above, except the gray boxes are filled in.

I found no way to PROVE what must go where!

I finally guessed:  B1 = 3.

I was right.  

Was it just a lucky guess?

I tried again with B1=8.  I was right again!

TWO POSSIBLE SOLUTIONS.

Awkward to phrase what's going on, but you might see how the symmetry in possible values allows two solutions.

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PB Post 2014  04 06 Lvl 5       (Repeated lower down)
Notable because... Hidden triple. Sadly, not required!

User might get beyond pink boxes because of 1/5 doubles found in Group 7.  But it's good to read explanation below the 2nd showing of this puzzle. It is an example of a "hidden" triple.

PB Post 2014 04 06 w 37      Same puzzle as above except the pink boxes are filled in.

Easiest solution is noticing Group 7, 1/5 doubles means that A7 cannot be a 1 or a 5.  That leaves G7 as the only 1 in its row.  Then in Group 9, 2/5 doubles mean that I8 cannot be 5, and so equals 9.  FINIS.

NOTE AN ALTERNATE METHOD starts with the same 1/5 double in Group 7 allowing you to eliminate 1 from A7,  But then, in row 7, recognize a "hidden" triple. The 2/7 , 5/7, and 2/5 doubles represent only 3 values available for 3 boxes. Therefore, 2, 5, and 7 can be eliminated from OTHER boxes in row 7.  This proves that A7 =8.      FINIS

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PB Post 2014 05 16  Lvl 5 (6) (Repeated lower down)

Notable because... triple required

PB Post 2014 05 16 Lvl 5 (6) w 38 Same as above, except the green boxes are filled in.

To proceed, note row 3 has a ?semi-naked? triple of 5,7,9. This allows you to cross those numbers out of the OTHER boxes in that row, leaving E3=6.  Eventually, you can finish.

PB Post 2014 05 18 Sunday Lvl 5

Open with two 2s, a 4, six (all) the 7s.  
Notice Group 7: Single-line elimination of 8s.
Column F: single-line elimination of 5
Row 9: 5/8 doubles
Column F: 1/6 doubles
Group 2: 5/9 doubles
.....
Later on, Group 4: single-line elimination of 1
Row 5: Hidden 1/6 pair
Column G: Hidden 2/4 pair
Group 6: 1/3/6 triple proves G4 = 8. 
Eventually finish.