Friday, February 21, 2014

PB Post 2014 Level 5 ............. January-June

MY criteria for level 5 puzzles is that they require noticing two pairs or two doubles (but NOT chains or coloring).
Therefore, in solving, I attempt to exhaust all naked singles, hidden singles, single-line eliminations, and double-line eliminations.
Sometimes, I will repeat the puzzle when it is partially done at this point.

PB Post 2014 01 03 Lvl 5



PB Post 2014 01 10 Lvl 5



PB Post 2014 01 12 Sunday Lvl 5 



PB Post 2014 01 17 Lvl 5



PB Post 2014 01 19 Sunday Lvl 5  (Repeated lower down)
Jan 19. Lots of Pairs. Good puzzle. Stopped several times, but finish.
Repeated lower with pinks filled in.



PB Post 2014 01 19 Sunday Lvl 5   Same puzzle as above except the pink boxes are filled in.
Note underlined tiny numbers can be eliminated. In columns C and D 2/9 pair.  In column E  3/5 pairs. When 31 left, I found B2=6 because columns A & C claimed by 6 in two lower groups.



PB Post 2014 01 24 Lvl 5
Here is a rigorous Level 5 puzzle. Requires detecting many PAIRS of "doubles" / "pairs"



PB Post 2014 01 26 Sunday Lvl 5




PB Post 2014 01 31 Lvl 5
Required about 2 pairs to solve.




PB Post 2014 02 02 Sunday  (Repeated lower down)

While I used coloring to eliminate some 1's, I don't know if it was necessary. Lots of eliminations based on finding two pairs in a "zone". Took a LONG TIME to enter a 9 anywhere!


PB Post 2014 02 02 Sunday This is the same puzzle as above except the green boxes are filled in.
(Note: Using "simple" methods, the 18 underlined numbers can be removed as choices.) 
In order to proceed, I used colors and multicolors. I don't know if that was all necessary. For colors, I used  1   and discovered that  C4 could not contain 1.
Then I continued using colors for 1. I used MULTI-COLORS for it, and found that  G4 could not equal 1.    I wrote myself a hint about next checking to eliminate 6's.





PB Post 2014 02 07 Lvl 5 (4) is posted with Level 4 puzzles.
PB Post 2014 02 09 Sunday Lvl 5 (6) is posted with Level 6 puzzles.
PB Post 2014 02 14 Lvl 5 (6) is posted with Level 6 puzzles.


PB Post 2014 02 16 Sunday Lvl 5

Like any good level 5, this required finding two pairs many times. Finished quickly.



PB Post 2014 02 21 Lvl 5

Almost a Level 4, except with 34 remaining, I used doubles that allowed me to find the 9 in column D.


PB Post 2014 02 23 Sunday Lvl 5





PB Post 2014 02 28 Lvl 5




PB Post 2014 03 09 Sunday Lvl 5




S


PB Post 2014 03 14 Lvl 5         (Repeated lower down)


PB Post 2014 03 14 w 44      Same puzzle as above except the green boxes are filled in.
(See note at top of this page explaining criteria for showing a puzzle such as this one, partially completed)
(Note: Using "simple" methods, the underlined 5 in C5 can be removed as a choice.)
To proceed with 44,  in Column D, find two 5/7 "doubles" which allows some eliminations. 
In column G find two 3/5 pairs, then 4/9 pairs. This leaves H5 with the only 4 in its group.  FINIS!



PB Post 2014 03 16 Lvl 5         (Repeated lower down)
A good, rigorous Level 5 puzzle.
The ease of the blue boxes is pretty arbitrary. This author CHOSE to refrain from using pairs or doubles while filling in those 9 blue boxes. There is absolutely no reason for others to follow such a choice.
I found lots of single-line and double-line eliminations.

PB Post 2014 03 16 w 45      Same puzzle as above except the green boxes are filled in.
Note: Using "simple" methods, the 17 underlined numbers (rows 1, 7, 8, and 9) can be removed as a choices.
Users may have already noted many things listed here:
To proceed with 45 in puzzle above, in Grp 1 there are 1/3 pairs and 5/8 pairs.
Grp 2 has 3/7 pairs. Col A has 2/6 pairs, then 5/9 doubles.The 8 in A6 became the only one in Col A.
With 44 Col F has 3/7 pairs.  Also in Column F 5/9 doubles imply F7 cannot be 9 and must be 6.
The final 43 answers were naked singles!




PB Post 2014 03 21 Lvl 5
[The following is merely comment on how the author solved. Users might go about it in a different order, resulting in totally different obstacles and solutions.]
Lots of naked singles began the puzzle. 7 was the first number to be filled in completely.
With 39 remaining, in Group 1, two 2/5 hidden doubles allows some eliminations. Keep checking for pairs and doubles along the top 3 rows for more.
With 33 remaining, in Column H two 8/9 doubles prove that H9 cannot be 8, so H9 = 5.
With 26 remaining, in Group 9, 8/9 doubles prove that I8 = 2.
It was still a struggle to finish, but eventually....FINIS.






PB Post 2014 03 23 Sun Lvl 5
Pretty easy. I needed a pair only one time: in row 5, I used a 5/9 pair to eliminate other numbers.Curiously, that 5/9 pair was available after my very first entry, the naked single 9 in H5. (I didn't notice it until I had filled in about 20 naked and hidden singles.)
Multiple alternatives undoubtedly avoid this use of that pair.






PB Post 2014 03 28 Lvl 5



PB Post 2014 03 30 Sun Lvl 5
[The following is merely comment on how the author solved. Users might go about it in a different order, resulting in totally different obstacles and solutions.]
Medium Level 5
With 45 remaining, I found - in column A - that I could eliminate 1's in one group. Thne I made use of 1/6 pairs, and of 4/8 pairs in Column A.
Later, with 42 remaining, I found - in Column E - 5/8 pairs, then 1/3 pairs (which revealed E6=9)





PB Post 2014  04 04 Lvl 5                (Repeated lower down)
Do the 7s first. Fast.
Green boxes required simplest techniques, but other users might easily fill other boxes in. The partially completed puzzle is repeated below for new Level  5 learners.
PB Post 2014 04 04 w 46      Same puzzle as above except the green boxes are filled in.
[The following is merely comment on how the author solved. Users might go about it in a different order, resulting in totally different obstacles and solutions.]
The UNDERLINED possibilities above were eliminated by several techniques. 
   In Group 3, notice the two 2/3 pairs which allows OTHER possibilities in I1 and I2 to be eliminated.
   In Group 5, notice that 1's in the two adjoining groups (4 & 6) are only found in ROWS 4 & 6. Thus, Group 5 must contain a 1 in row 5, eliminating other 1s in group 5.
   Looking at the possibilities for 8 in columns G and I leads to crossing them out of those two columns in Group 3.
  While other method will work, interesting to note in Group 5, the 1/6/8 triple in row 5 of that groups allows elimination of 8 from E4 and F4.  (Other method: single row of 8's in Group 6).
 (MAYBE some answers got filled in?) but I soon used a 4/5 double found in group 3.
 Solution followed pretty soon afterwards.
   


PB Post 2014  04 06 Lvl 5       (Repeated lower down)
  Notable puzzle because... Hidden triple. Sadly, not required!
User might get beyond pink boxes because of 1/5 doubles found in Group 7.  But it's good to read explanation below the 2nd showing of this puzzle. It is an example of a "hidden" triple.

PB Post 2014 04 06 w 37      Same puzzle as above except the pink boxes are filled in.

Easiest solution is noticing Group 7, 1/5 doubles means that A7 cannot be a 1 or a 5.  That leaves G7 as the only 1 in its row.  Then in Group 9, 2/5 doubles mean that I8 cannot be 5, and so equals 9.  FINIS.

NOTE AN ALTERNATE METHOD starts with the same 1/5 double in Group 7 allowing you to eliminate 1 from A7,  But then, in row 7, recognize a "hidden" triple. The 2/7 , 5/7, and 2/5 doubles represent only 3 values available for 3 boxes. Therefore, 2, 5, and 7 can be eliminated from OTHER boxes in row 7.  This proves that A7 =8.      FINIS


PB Post 2014 04 13 Sun Lvl 5
Had many hidden pairs. Average Level 5.




PB Post 2014 04 18 Lvl 5



PB Post 2014 04 20 Sun Lvl 5



PB Post 2014 04 25 Lvl 5
The comments here may not reflect the user's experience, since they depend on the order of finding answers. 
At first, a naked 5 and a naked 3 were found.
Then ALL of the 8's were easily filled in.
With 37 remaining, in Row 5 I found a 1/3 double, allowing some eliminations.
In GROUP 3, a (hidden) pair of 3/7's  allowed me to eliminate and prove that I3 =4, then I9 = 2,  A1 = 2.
Eventually finished.


PB Post 2014 04 27 Sun Lvl 5
Felt like cheating, but I had computer program highlight pairs after only one naked single was found. In group 1, there was a 1/7 pair, and in group 7 there was a 4/5 pair. These allowed eliminations that apparently made the puzzle easy.  FINIS

PB Post 2014 05 01 Lvl 4 (5)
Newspaper calls this a Level 4, but I used (perhaps not required) double-line elimination of 9's (in Gp 9, then Gp 8). Stubborn puzzle. I call it a Level 5

SchuDoku Home

PB Post 2014 05 09 Lvl 5
I first found two 2's, then a 4.
Seven naked singles
In group 3, 1/5 pairs allowed some eliminations.
In ROW 7, 3/7 pairs allowed eliminations and resulted in D9=6.
All the 2's were then filled in.
Naked singles finished the puzzle.


SchuDoku Home

PB Post 2014 05 18 Sunday Lvl 5
Open with two 2s, a 4, six (all) the 7s.  
Notice Group 7: Single-line elimination of 8s.
Column F: single-line elimination of 5
Row 9: 5/8 doubles
Column F: 1/6 doubles
Group 2: 5/9 doubles
.....
Later on, Group 4: single-line elimination of 1
Row 5: Hidden 1/6 pair
Column G: Hidden 2/4 pair
Group 6: 1/3/6 triple proves G4 = 8. 
Eventually finish.




PB Post 2014 05 23 Lvl 5

Here's my order of solving. Users may successfully solve in a totally different fashion:
No naked singles to start!
I found a 1, 6, two 7s, two 9s, then a 5, two 6's.
With all the green boxes filled in, there were 46 remaining. See next puzzle:

PB Post 2014 05 23 w 46      Same puzzle as above except the green boxes are filled in.
With 46 remaining:
In group 6, hidden 6/8 pairs allowed some eliminations.
Then, in row 4, a 2/3/5 triple proved that D4 = 7.
After that, two more 7s
In group 1, vertical double-line elimination of 3's
Row 5: single-line elimination of 5s.
Then 6 naked singles.
Then a 5, a 6, two 8s, and finally a slew of naked singles to finish.




PB Post 2014 05 26 Sun Lvl 5
Good Level 5 puzzle.
My chronicle:  2 naked singles.
 Then three 1s, 2, 4,
 Column C: single-line elimination of 5s.
 6
Row 6: Single line eliminations of 8
9, 7, 2
Row 6: Sinlge line eliminations of 3, then of 4, then triple 1/6/8 proves that A6 = 5
Row 5: 5/6 double
Row 1: 4/7 pair proves G1 =3
8 naked singles
2, 3
29 naked singles   FINIS


PB Post 2014 06 01 Sunday Lvl 5  
Repeated lower with green filled in. 
Green boxes do not require hidden pairs, nor double-line eliminations.
Chronicle:
   I found a 4;
   Then in Column B, single-line eliminations of 5
   Then two 8s, two 9s, an 8
   Column D: 1/2 double allows eliminations proving D6=3
   Row 7: Single line eliminations of 2
   Then three 3s.
   Then 5 naked singles.
   That left me with the next view:


PB Post 2014 06 01 Sunday Lvl 5 w 38   Same puzzle as above except the green boxes are filled in.
To continue from here, with 38 to go:
    In rows 1 and 2: double-line eliminations of 1
    Then I found a 2, 4, two 5s.
     Rows 4 and 6 allowed double-line eliminations of 2
    Then I filled in two 2s before completing with 32 naked singles.



PB Post 2014 06 05 Lvl 4 (5)
 Chronical of my solution. User may go about it differently.
2, five (all) 4s, four (all) 6s, 7, 1, three 2s
Three naked singles
3
With 34: Column F's: single-line elimination of 3s
Rows 7 and 8: double-line elimination of 7 proves that B9 = 3   (earned the level 5 designation)
Row 8: Single-line elimination of 9s;
Row 2: Single-line elimination of 1 proves C3 = 1;
32 naked singles. 



PB Post 2014 06 08 Sunday Lvl 5    (Repeated lower down)
A good, rigorous Level 5 puzzle.
Advanced users might easily fill in boxes that are not shaded green. Green boxes do not require hidden pairs, but some single and double-line eliminations were employed.

PB Post 2014 06 08 Sunday w 37    Same puzzle as above except the green boxes are filled in.
Using "simple" methods ... NOT requiring hidden singles... the 14 underlined possibilities can be eliminated.
To continue after that, I first noted in Column C there was a "hidden" 1/3 pair. I'm not sure that was necessary.
Next I found Row 6 a hidden 6/8 pair. This allowed me to determine that F6 = 7.
36 naked singles finished the puzzle.



PB Post 2014 06 13 Lvl 5
The comments here may not reflect the user's experience, since they depend on the order of finding answers. 
13 naked singles
4
Row 1 / Group 1: 1/2 double allows eliminations
Column A: 5/6 double leads to two naked singles: 7 and 4

Then a 7 then two 1s.
Group 1: 6/7 double produces eliminations.

Finally: in Group 1, a 3/8 pair allows eliminations.
Soon a 9 is found, then a 5.
And 34 naked singles finish the puzzle.

SchuDoku Home

PB Post 2014  Lvl 5

No comments:

Post a Comment